When x-ray exposure at 60 inches results in an intensity of 100 μGy, what will be the intensity at 72 inches?

Study for the RTBC Advanced Exposure Factors Test. Study with flashcards and multiple choice questions, each question has hints and explanations. Get ready for your exam!

To determine the intensity of x-ray exposure at a different distance, you can use the inverse square law, which states that the intensity of radiation is inversely proportional to the square of the distance from the source. This means that as the distance increases, the intensity decreases according to the formula:

[ I_1 / I_2 = (D_2 / D_1)^2 ]

where:

  • ( I_1 ) is the original intensity,

  • ( I_2 ) is the new intensity,

  • ( D_1 ) is the original distance,

  • ( D_2 ) is the new distance.

In this scenario:

  • The original intensity ( I_1 ) is 100 μGy,

  • The original distance ( D_1 ) is 60 inches,

  • The new distance ( D_2 ) is 72 inches.

Using the formula:

  1. Calculate the ratio of the distances:

[

\frac{D_2}{D_1} = \frac{72}{60} = 1.2

]

  1. Square the ratio:

[

(1.2)^2 = 1.44

]

3

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